# How many unique gametes could be produced from a parent who is AaBbCC?

Contents
No. of homologous chromosome pairs (heterozygous genes) No. of different gametes from each parent
1 (Aa X Aa) 2 (21)
2 (AaBb X AaBb) 4 (22)
3 (AaBbCc X AaBbCc) 8 (23)
4 (AaBbCcDd X AaBbCcDd) 16 (24)

## How many allele combinations are in AaBbCC?

Possible gametes for each AaBb parent

Since each parent has four different combinations of alleles in the gametes, there are sixteen possible combinations for this cross. Therefore we use a 4 square by 4 square Punnett Square.

## How many gamete possibilities will you get from a parent who is AaBbccDDEeFFGG?

a) An individual with the genotype AaBbccDDEeFFGG produces 8 different gametes. b) A cross between two AaBbCcDd parents yields 81 different genotypes.

## What skin color is AaBbCc?

 Someone who is aabbcc would have very light skin color. If a person who had the AABBCC genotype and a person with the aabbcc genotype had children ..  their children would all be the AaBbCc genotype  and have a ‘mid-brown skin’ phenotype.

## How many unique gametes can be produced?

How many unique gametes could be produced through independent assortment by an individual with genotype – AaBbCCDdEE? The answer is eight. Eliminate the Cs and the Es — since the individual is homozygous at those loci, they can only produce one kind of gamete (with a C and an E).

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## How many unique gametes can be produced from a cross?

The number of different possible gametes produced by the diploid genotype (AaBbCcDdEe) is 2 x 2 x 2 x 2 x 2 = 32 (2 for each pair of heterozygous genes).

## How many allele combinations are in RrYY?

Mendelian Genetics